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A Cylindrical Example |
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Let us now convert our Cartesian test problem into a cylindrical one. If we rotate the box and blob around the left boundary, we will form a torus between two circular plates (like a donut in a round box).
These changes will be required:
The full script, converted to cylindrical coordinates is then:
TITLE 'Heat flow around an Insulating Torus' COORDINATES YCYLINDER VARIABLES Phi { the temperature } DEFINITIONS K = 1 { default conductivity } Rad = 0.5 { blob radius (renamed)} EQUATIONS Div(-k*grad(phi)) = 0 BOUNDARIES REGION 1 'box' START(0,-1) VALUE(Phi)=0 LINE TO (2,-1) NATURAL(Phi)=0 LINE TO (2,1) VALUE(Phi)=1 LINE TO (0,1) NATURAL(Phi)=0 LINE TO CLOSE REGION 2 'blob' { the embedded blob } k = 0.001 START 'ring' (1,Rad) ARC(CENTER=1,0) ANGLE=360 TO CLOSE PLOTS CONTOUR(Phi) VECTOR(-k*grad(Phi)) ELEVATION(Phi) FROM (1,-1) to (1,1) ELEVATION(Normal(-k*grad(Phi))) ON 'ring' END
The resulting contour and boundary plot look like this:
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