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Patrick Temple (ptemple)
New member
Username: ptemple

Post Number: 1
Registered: 09-2003
Posted on Tuesday, September 23, 2003 - 03:34 am:   

I am trying to find the electromagnetic resonant modes for a hollow cavity cylinder. I have started by using the standard wave equation for Ez but am having trouble determining the boundary condition for the r=0 axis of symmetry. Should it be Natural(Ez) = 0 for the r=0 line?
Thanks for any help,
Patrick
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Robert G. Nelson (rgnelson)
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Username: rgnelson

Post Number: 41
Registered: 06-2003
Posted on Tuesday, September 23, 2003 - 02:29 pm:   

If your equation is, as I infer, something like div(grad(Ez))+lambda*Ez=0, then the Natural BC specifies the outward normal component of grad(Ez). At the rotation axis, you want this to be zero, so NATURAL(Ez)=0 is the correct boundary condition.
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Patrick Temple (ptemple)
New member
Username: ptemple

Post Number: 2
Registered: 09-2003
Posted on Tuesday, September 30, 2003 - 05:46 pm:   

Thanks for your quick reply. That worked for finding the resonant modes for a smooth metal cavity. I am now trying to find the eigenvalues for an axially symmetric cavity which has angled exterior walls. This means that Ez will be non-zero at these walls and the E vector must still be normal to the exterior walls. Is there a good way to set this boundary condition which ties in a whole new variable Er? Am I making this problem more complicated than it has to be?
Thanks again,
Patrick
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Robert G. Nelson (rgnelson)
Moderator
Username: rgnelson

Post Number: 42
Registered: 06-2003
Posted on Wednesday, October 01, 2003 - 04:50 pm:   

Since you now have two variables, Er and Ez, you need two boundary conditions. One of them could be value(Er)=(nr/nz)*Ez, to force E normal to the wall. Is there another condition you can impose on Ez or its derivative?

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