| Author | Message | ||
     Kevin Ellwood (ikevin) Member Username: ikevin Post Number: 18 Registered: 06-2003 |
Hello I would like to be able to perform the following calculation: tintegral(u) at (1,1) where "u" is a "variable" unkown that is a solution to a pde. Is there a way to do this with flexpde 4.0? Thanks | ||
| Robert G. Nelson (rgnelson) Moderator Username: rgnelson Post Number: 154 Registered: 06-2003 |
The function VAL(<expression>,<x>,<y>) will return the value of <expression> at the stated coordinates (which must be constants). Tintegral(VAL(u,1,1)) should give you what you want. The function EVAL() is syntactically the same as VAL(), but the coordinates themselves can be the result of expression evaluation. See VAL and EVAL in the Help Index. | ||
| Kevin Ellwood (ikevin) Member Username: ikevin Post Number: 19 Registered: 06-2003 |
Worked perfectly. Thanks |