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gehong (gehong518)
New member
Username: gehong518

Post Number: 2
Registered: 12-2006
Posted on Tuesday, December 12, 2006 - 09:27 am:   

application/mswordmy script
Hello.doc (36.9 k)

Hello, G. Nelson
I am new to the software, and I have a trouble on boundary condition. I tried to solve a PDE problem in the attachment in a 2D-rectangular region.I have read most of the documentation and examples. However, I couldn't find the answer for, in provided documentation/help/examples.
I hope I can get your help.
Thanks!
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Robert G. Nelson (rgnelson)
Moderator
Username: rgnelson

Post Number: 713
Registered: 06-2003
Posted on Wednesday, December 13, 2006 - 03:28 pm:   

If you use the Vb=Vt condition as a Boundary condition on Vb, as you have indicated in your script (applied over the entire boundary), you still need to supply a BC for Vt.

The Natural BC for Vt specifies (in your equation system) the outward normal derivative of Vt. (See Natural BC in the Help Index).

From your equation (2),
dn(Vt) = -[dsubt/d(x,y)]*dn(Vb)

So the specification
NATURAL(Vt) = -[dsubt/d(x,y)]*NORMAL(GRAD(Vb))
should do what you want.

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