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gehong (gehong518)
New member Username: gehong518
Post Number: 2 Registered: 12-2006
| Posted on Tuesday, December 12, 2006 - 09:27 am: | |
Hello, G. Nelson I am new to the software, and I have a trouble on boundary condition. I tried to solve a PDE problem in the attachment in a 2D-rectangular region.I have read most of the documentation and examples. However, I couldn't find the answer for, in provided documentation/help/examples. I hope I can get your help. Thanks!
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Robert G. Nelson (rgnelson)
Moderator Username: rgnelson
Post Number: 713 Registered: 06-2003
| Posted on Wednesday, December 13, 2006 - 03:28 pm: | |
If you use the Vb=Vt condition as a Boundary condition on Vb, as you have indicated in your script (applied over the entire boundary), you still need to supply a BC for Vt. The Natural BC for Vt specifies (in your equation system) the outward normal derivative of Vt. (See Natural BC in the Help Index). From your equation (2), dn(Vt) = -[dsubt/d(x,y)]*dn(Vb) So the specification NATURAL(Vt) = -[dsubt/d(x,y)]*NORMAL(GRAD(Vb)) should do what you want.
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