    
esme
New member
Username: esme
Post Number: 1
Registered: 03-2010
| | Posted on Monday, March 29, 2010 - 08:43 pm: | |
I'm new to flexpde so this is likely (and hopefully) a simple question, but I've not been able to find anything in the manual.
I'm looking to solve a pde of the form V'' + (t - y)V = V^3. While V is a fcn of t and y I can effectively treat t as a known value and solve V as an ode. The problem is my boundary conditions are V = 0 at the ends of the domain and I need to force the solution away from the zero solution. In the past I've used Matlab for problems such as these by solving for t as a parameter allowing me to introduce an additional boundary condition for V' to force from the zero solution. This then gives me the t values that match to the V' set on the boundary - stepping through V' values gives me the full range of possible solutions.
Is this possible in flexpde? If anyone could point me to a demo that does a problem similar to this or a method I should be looking at it'd be much appreciated.
Thanks
Esme |