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Steve Strand (srstrand)
New member
Username: srstrand

Post Number: 1
Registered: 02-2006
Posted on Tuesday, February 28, 2006 - 01:12 pm:   

For a problem in r and z,
I need to use in the equations a definite integral over r of a field variable at z locations.
How can this be done?
i.e.
dz(U * C) = ...
U = surf_integral(g(C)) over r at z

The U variable is an average value over r instead of a mesh-point variable.
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Robert G. Nelson (rgnelson)
Moderator
Username: rgnelson

Post Number: 554
Registered: 06-2003
Posted on Tuesday, February 28, 2006 - 04:13 pm:   

Define a boundary at the path you want to integrate (use a named FEATURE).
Then include
U = surf_integral(g(c), <path_name>)
in your Definitions section.

See for example "Backstrom_Books | Fields_of_Physics | b_Electricity | elec14a.pde"
Or
"Samples | Misc | Constraints | Bdry_Constraint.pde"

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Steve Strand (srstrand)
New member
Username: srstrand

Post Number: 2
Registered: 02-2006
Posted on Thursday, March 02, 2006 - 11:11 am:   

This problem requires a value of the integral over r at every z point. It doesn't sound like this capability exists in FlexPDE. Another way to do this problem is to differentiate the integral equation to yield a new differential equation. We would then need the value of the integrated function at the boundaries as a continous function in z.
So what is needed is the ability to write an expression that includes the value of one of the field variables as a function, not just at a point. The VAL and EVAl functions allow sampling of a field variable at a point. Is there a capability for continuous sampling of the field variable along a boundary for use in the differential equations?
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Robert G. Nelson (rgnelson)
Moderator
Username: rgnelson

Post Number: 558
Registered: 06-2003
Posted on Thursday, March 02, 2006 - 08:54 pm:   

An integral is the inverse of a derivative. If I=R_Integral(g(c)) then dr(I)=g(c).
This can be posed as a PDE. Make I a variable and give it the equation above. Integrating differential equations is what FlexPDE does.

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